log(16+2b)=(b^2-4b)

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Solution for log(16+2b)=(b^2-4b) equation: 


Simplifying
log(16 + 2b) = (b2 + -4b)
(16 * glo + 2b * glo) = (b2 + -4b)

Reorder the terms:
(2bglo + 16glo) = (b2 + -4b)
(2bglo + 16glo) = (b2 + -4b)

Reorder the terms:
2bglo + 16glo = (-4b + b2)

Remove parenthesis around (-4b + b2)
2bglo + 16glo = -4b + b2

Solving
2bglo + 16glo = -4b + b2

Solving for variable 'b'.

Reorder the terms:
4b + 2bglo + -1b2 + 16glo = -4b + b2 + 4b + -1b2

Reorder the terms:
4b + 2bglo + -1b2 + 16glo = -4b + 4b + b2 + -1b2

Combine like terms: -4b + 4b = 0
4b + 2bglo + -1b2 + 16glo = 0 + b2 + -1b2
4b + 2bglo + -1b2 + 16glo = b2 + -1b2

Combine like terms: b2 + -1b2 = 0
4b + 2bglo + -1b2 + 16glo = 0

The solution to this equation could not be determined.

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